灵山人印象，勿喷

xieyongxin

求解微分方程 y'=a/y+b
问题补充：dx=[y/(a+by)]dy=[(1/b)-a/(b*b*y+a)]dy应为dx=[y/(a+by)]dy={(1/b)-a/[b*(b*y+a)]}dy解方程哈哈